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225=(3.14r^2)
We move all terms to the left:
225-((3.14r^2))=0
We calculate terms in parentheses: -((3.14r^2)), so:We get rid of parentheses
(3.14r^2)
We get rid of parentheses
3.14r^2
Back to the equation:
-(3.14r^2)
-3.14r^2+225=0
a = -3.14; b = 0; c = +225;
Δ = b2-4ac
Δ = 02-4·(-3.14)·225
Δ = 2826
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2826}=\sqrt{9*314}=\sqrt{9}*\sqrt{314}=3\sqrt{314}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-3\sqrt{314}}{2*-3.14}=\frac{0-3\sqrt{314}}{-6.28} =-\frac{3\sqrt{314}}{-6.28} =-\frac{\sqrt{314}}{-2.0933333333333} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+3\sqrt{314}}{2*-3.14}=\frac{0+3\sqrt{314}}{-6.28} =\frac{3\sqrt{314}}{-6.28} =\frac{\sqrt{314}}{-2.0933333333333} $
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